목차/차례
BJT 실습
Simulation Using Smart-spice
Bipolar Junction Transistor
(c)
NPN Bipolar Junction Transistor
BJT
.option scale=1u post
.dc VBE 0 0.8 1m VCE 0 5 1
VCE VCE 0 DC 1
VBE VBE 0 DC 0
Q1 VCE VBE 0 0 Q2N3904
.model Q2N3904 NPN (Is=6.734f Xti=3 Eg=1.11 Vaf=5.03 Bf=416.4
+ Ne=1.259 Ise=6.734f Ikf=66.78m Xtb=1.5 Br=.7371 Nc=2 Isc=0
+ Ikr=0 Rc=0.1 Cjc=3.638p Mjc=.3085 Vjc=.75 Fc=.5 Cje=4.493p
+ Mje=.2593 Vje=.75 Tr=239.5n Tf=301.2p Itf=.4 Vtf=4 Xtf=2 Rb=10)
.let IC=-i(VCE...
본문/내용
BJT 실습
Simulation Using Smart-spice
Bipolar Junction Transistor
(c)
NPN Bipolar Junction Transistor
BJT
.option scale=1u post
.dc VBE 0 0.8 1m VCE 0 5 1
VCE VCE 0 DC 1
VBE VBE 0 DC 0
Q1 VCE VBE 0 0 Q2N3904
.model Q2N3904 NPN (Is=6.734f Xti=3 Eg=1.11 Vaf=5.03 Bf=416.4
+ Ne=1.259 Ise=6.734f Ikf=66.78m Xtb=1.5 Br=.7371 Nc=2 Isc=0
+ Ikr=0 Rc=0.1 Cjc=3.638p Mjc=.3085 Vjc=.75 Fc=.5 Cje=4.493p
+ Mje=.2593 Vje=.75 Tr=239.5n Tf=301.2p Itf=.4 Vtf=4 Xtf=2 Rb=10)
.let IC=-i(VCE)
.plot IC
.end
Gateway simulation
.dc LIN VBE 0 0.8 1m LIN VCE 0 5 1
.model Q2N3904 NPN (Is=6.734f Xti=3 Eg=1.11 Vaf=5.03 Bf=416.4
+ Ne=1.259 Ise=6.734f Ikf=66.78m Xtb=1.5 Br=.7371 Nc=2 Isc=0
+ Ikr=0 Rc=0.1 Cjc=3.638p Mjc=.3085 Vjc=.75 Fc=.5 Cje=4.493p
+ Mje=.2593 Vje=.75 Tr=239.5n Tf=301.2p Itf=.4 Vtf=4 Xtf=2 Rb=10)
NPN Bipolar Junction Transistor
BJT
.option scale=1u post
.dc VCE 0 5 1m VBE 0 5 1
VCE VCE 0 DC 5
VBE VBE 0 DC 0
Q1 VCE VBE 0 0 Q2N3904
.model Q2N390…
.05n Tf=179.3p Itf=.4 Vtf=4 Xtf=6 Rb=10)
.let IC=i(VCE)
.plot IC
.end
Gateway simulation
.dc LIN VBE 0 -0.8 -1m LIN VCE 0 -5 -1
.model Q2N3905 PNP(Is=1.41f Xti=3 Eg=1.11 Vaf=18.7 Bf=90.35
+ Ne=1.5 Ise=0 Ikf=80m Xtb=1.5 Br=5.502 Nc=2 Isc=0
+ Ikr=0 Rc=2.5 Cjc=9.728p Mjc=.5776 Vjc=.75 Fc=.5 Cje=8.063p
+ Mje=.3677 Vje=.75 Tr=35.05n Tf=179.3p Itf=.4 Vtf=4 Xtf=6 Rb=10)
Gateway의 경우 Smart-spice와 달리 노드로 들어가는 전류를 측정하므로 Ic전류파형을 보게 될 경우 부호가 반대로 나오게 됩니다.
따라서 Ic전류와 유사한 Ie전류를 측정하기 바랍니다.
Smart-spice와 같은 Ic전류파형을 보기 위해서는 Smartview의
Calculator를 사용하여 (-)부호를 취해주시기 바랍니다.
PNP Bipolar Junction Transistor
BJT
.option scale=1u post
.dc VCE 0 -10 -1m VBE 0 -5 -1
VCE VCE 0 DC -5
VBE VBE 0 DC 0
Q1 VCE VBE 0 0 Q2N3905
.model Q2N3905 PNP(Is=1.41f Xti=3 Eg=1.11 Vaf=18.7 Bf=90.35
+ Ne=1.5 Ise=0 Ikf=80m Xtb=1.5 Br=5.502 Nc=2 Isc=0
+ Ikr=0 Rc=2.5 Cjc=9.728p Mjc=.5776 Vjc=.75 Fc=.5 Cje=8.063p
+ Mje=.3677 Vje=.75 Tr=35.05n Tf=179.3p Itf=.4 Vtf=4 Xtf=6 Rb=10)
.let IC=i(VCE)